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Figure out that math problem!


Sableye

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You have to solve an easy math equation.

You put your answer on your post then

You put an Harder Equation up there and some one will solve it

then so on until there's an equation too high for anyone to solve.

Then we start over.

Also post what post it is like

My topic is post 1 (seriously)

Your post after mine wil be 2 and so on.

2+2=?

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8^(1/2) = SQRT{8} = 2.83 (rounded)

Solve for x:

x^2-3x-40=0

(x squared minus 3x minus 40 equals zero)

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dy2          dy

-----  + 7 ----  + 10y = 4te-3t    ; the initial values are y(0) =0 ; y'(0) =-1

dx2         dx

find y(t) 

(hint, you need to use Laplace transformation and inverse Laplace transformation to change from t to s domain and backwards)

for DZ's problem:

x is -5 and 8

edit: umm forget mine, I didn't read the "put a harder one not whatever you want"  :lol: go for ummm... x^3+x^2+x+10=x , I guess

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edit: umm forget mine, I didn't read the "put a harder one not whatever you want"  :lol: go for ummm... x^3+x^2+x+10=x , I guess

Took me a bit longer than I expected, but...

x^3+x^2+x+10=x

simplifies to

x^3 + x^2 = -10

and since it wasn't a particularly easy polynomial to solve, I used the graphical method

as a result, the x value is approximately equal to -2.5445 (remaining digits unknown)

plugged into the equation, it results in

-16.4743 + 6.4744 = -10

-9.9999 = -10

(close enough)

----------------------------

Take a given point, and two vectors pointing out of it:


           *
          /  
         /    
        V      V


Allowing either or both of those vectors to rotate about the vector pointing straight up (towards your face), you can see that you can generate any angle between these two vectors.

Now, show the method of finding the inverse middle vector. That is, the vector that points away from the middle of the two vectors. The center of the two vectors are whichever order will lead to the smallest angle between them.


           ^
           |  ----- inverse middle vector
           |
           *
          /  
         /    
        V      V

Do not assume that any of the vectors are initially equal length.

There are multiple solutions to this problem, but one is very easy.

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dy2          dy

-----  + 7 ----  + 10y = 4te-3t    ; the initial values are y(0) =0 ; y'(0) =-1

dx2         dx

find y(t) 

That brings back unpleasant calculus memories....

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And yeah, the only way to easily solve that was with the graphical method, unless you like to take hours with the synthetic division, it also has an imaginary solution.

Alright then, let's go for something harder, but still not as hard as Laplace....basic calculus it is!

derivate....x3+(1/x2)+2

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